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Avoid cases of filenames Update years in terms and other legal(ish) documents Don't update years in license headers, since change is not meaningful Will add linter rule in seperate commit Happy recompiling everyone! Original Patch By: Nescio Comment By: Gallaecio Differential Revision: D2620 This was SVN commit r27786.
69 lines
2.5 KiB
C++
69 lines
2.5 KiB
C++
/* Copyright (C) 2020 Wildfire Games.
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* This file is part of 0 A.D.
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*
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* 0 A.D. is free software: you can redistribute it and/or modify
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* it under the terms of the GNU General Public License as published by
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* the Free Software Foundation, either version 2 of the License, or
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* (at your option) any later version.
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*
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* 0 A.D. is distributed in the hope that it will be useful,
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* but WITHOUT ANY WARRANTY; without even the implied warranty of
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* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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* GNU General Public License for more details.
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*
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* You should have received a copy of the GNU General Public License
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* along with 0 A.D. If not, see <http://www.gnu.org/licenses/>.
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*/
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#ifndef INCLUDED_SERIALIZETEMPLATES
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#define INCLUDED_SERIALIZETEMPLATES
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/**
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* @file
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* Helper templates definitions for serializing/deserializing common objects.
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*
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* Usage:
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* You need to (partially) specialize SerializeHelper for your type.
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* The optional SFINAE argument can be used to provide generic specializations
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* via std::enable_if_t<T>.
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* If both paths are common, you can templatize operator()'s first argument,
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* but you will need to templatize the passed value to account for different value categories.
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*
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* See SerializedTypes.h for some examples.
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*
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*/
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#include "simulation2/serialization/ISerializer.h"
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#include "simulation2/serialization/IDeserializer.h"
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// SFINAE is just there to allow SFINAE-partial specializations.
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template <typename T, typename SFINAE = void>
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struct SerializeHelper
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{
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template<typename... Args>
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void operator()(ISerializer& serialize, const char* name, T value, Args&&...);
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template<typename... Args>
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void operator()(IDeserializer& serialize, const char* name, T& value, Args&&...);
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};
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// This is the variant for an explicitly specified T (where what you pass is another type).
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template <typename T, typename S, typename... Args>
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void Serializer(S& serialize, const char* name, Args&&... args)
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{
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SerializeHelper<std::remove_const_t<std::remove_reference_t<T>>>()(serialize, name, std::forward<Args>(args)...);
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}
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// This lets T be deduced from the argument.
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template <typename T, typename S, typename... Args>
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void Serializer(S& serialize, const char* name, T&& value, Args&&... args)
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{
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SerializeHelper<std::remove_const_t<std::remove_reference_t<T>>>()(serialize, name, std::forward<T>(value), std::forward<Args>(args)...);
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}
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namespace Serialize
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{
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template<typename S, class T>
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using qualify = std::conditional_t<std::is_same_v<S, ISerializer&>, const T&, T&>;
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}
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#endif // INCLUDED_SERIALIZETEMPLATES
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